已知a/b=1/3,计算a²-2ab-b²/a²-3ab+b²的值

问题描述:

已知a/b=1/3,计算a&sup2-2ab-b&sup2/a&sup2-3ab+b&sup2的值

a/b=1/3,
b=3a
原式=(a^2-6a^2-9a^2)/(a^2-9a^2+9a^2)
=(1-6-9)/(1-9+9)
=-14