设函数f(x)=-1/3x~3+2ax~2-3a~2x+1(0

问题描述:

设函数f(x)=-1/3x~3+2ax~2-3a~2x+1(0

答:
(1).
f'(x)=-x^2+4ax-3a^2=-(x-a)(x-3a),其中(0