已知a(a-1)-(a²-b)=2,求(a²+b²)/2-ab的值

问题描述:

已知a(a-1)-(a&sup2-b)=2,求(a&sup2+b&sup2)/2-ab的值

a(a-1)-(a²-b)=2
a²-a-a²+b=2
b-a=2
(a²+b²)/2-ab
=(a²-2ab+b²)/2
=(b-a)²/2
=4/2
=2