解方程组：x+2y+3z＝62x+3y+z＝63x+y+2z＝6．
问题描述：
解方程组：
．
x+2y+3z＝6 2x+3y+z＝6 3x+y+2z＝6
答
x+2y+3z＝6①2x+3y+z＝6②3x+y+2z＝6③，①+②+③得6x+6y+6z=18，所以x+y+z=3④，②-①得x+y-2z=0⑤，④-⑤得3z=3，解得z=1，③-①得2x-y-z=0⑥，④+⑥得3x=3，解得x=1，把x=1，z=1代入④得1+y+1=3，解得y=1，所以原...