sin2α-2sin²α最小值,
问题描述：
sin2α-2sin²α最小值,
答
sin2α-2sin²α
=sin2a+(1-2sin²a)-1
=sin2a+cos2a-1
=√2(sin2acosπ/4+cos2asinπ/4)-1
=√2sin(2a+π/4)-1
所以当sin(2a+π/4)=-1时有最小值为：-√2-1