关于二次根式,

问题描述:

关于二次根式,
化简:
(√6+4√3+3√2)÷(√18+√12+3+√6)

原式=(√3*√2+4*√3+√3*√6)/(√3*√6+√4*√3+√3*√3+√2*√3)
=(√2+4+√6)/(√6+2+√3+√2)
=(√2+2 +2 +√6)/(√6+√3 + 2+√2)
=[√2(√2+1)+√2(√2+√3)]/[√3(√2+1)+√2(√2+1)]
=[√2(√2+1)+√2(√2+√3)]/[(√3+√2)(√2+1)]
=√2/(√3+√2) + √2/(√2+1)
=√2(√3-√2)+√2(√2-1)
=√6-2+2-√2
=√6-√2