计算:[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y

分类: 作业答案 • 2021-12-18 12:13:51

问题描述：

答

[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y
=(2x^3y^2-2x^2y)/3x^2y
=2/3xy-2/3