设siny-e^x+xy^2=0,求dy/dx
问题描述：
设siny-e^x+xy^2=0,求dy/dx
答
siny-e^x+xy^2=0
cosy.y' -e^x + 2xy.y' +y^2 =0
(cosy+2xy)y' = e^x-y^2
y' = (e^x-y^2)/(cosy+2xy)