cos^4x-sin^4x 2sin^2x=
问题描述:
cos^4x-sin^4x 2sin^2x=
答
cos^4x-sin^4x+2sin^2x
=(cos^2x+sin^2x)(coa^2x-sin^2x)+2sin^2x
=coa^2x-sin^2x+2sin^2x
=cos^2x+sin^2x
=1