(-3)的0次方-根号27+(1-根号2的绝对值)+1除根号3加根号2
问题描述:
(-3)的0次方-根号27+(1-根号2的绝对值)+1除根号3加根号2
答
(-3)的0次方-根号27+(1-根号2的绝对值)+1除根号3加根号2
(-3)的0次方=1
根号27=3*(根号3)
(1-根号2的绝对值)=(根号2)-1
1除(根号3加根号2)=(根号3)-(根号2)
则
(-3)的0次方-根号27+(1-根号2的绝对值)+1除根号3加根号2
=1-3*(根号3) +(根号2)-1+(根号3)-(根号2)
=1-2*(根号3)