求化简（1）sin10°分之1减去cos10°分之根号3,
问题描述：
求化简（1）sin10°分之1减去cos10°分之根号3,
答
(1/sin10)-(√3/cos10)
=(cos10-√3sin10)/sin10cos10
=[4(1/2cos10-√3/2sin10)]/sin20
=[4sin(30-10)]/sin20
=4
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