15(4x-8)-5(2x+10)-6(5x-20)-6(5x-20)=0怎么算啊?
问题描述:
15(4x-8)-5(2x+10)-6(5x-20)-6(5x-20)=0怎么算啊?
答
15(4x-8)-5(2x+10)-6(5x-20)-6(5x-20)=0
60x-120-10x-50-30x+120-30x+120=0
60x-10x-30x-30x=120+50-120-120
-10x=-70
x=7是-7.