y=ln(x的平方-2),则dy/dx=?
问题描述：
y=ln(x的平方-2),则dy/dx=?
答
dy=dln(x²-2)
=[1/(x²-2)]d(x²-2)
=[1/(x²-2)]*2xdx
所以dy/dx=2x/(x²-2)