求函数y=cos(x^2)·sin^2(1/x)的微分dy .
问题描述:
求函数y=cos(x^2)·sin^2(1/x)的微分dy .
答
y=cos(x^2)·sin^2(1/x)y'=-2xsin(x²)sin²(1/x)+cos(x²)2sin1/x cos1/x ·-1/x² =-2xsin(x²)sin²(1/x)-1/x² cos(x²)sin2/x 所以dy=【-2xsin(x²)si...