求函数y=log1/2[2sin(2x+π/3)-1]的单调区间,请写出过程.
问题描述:
求函数y=log1/2[2sin(2x+π/3)-1]的单调区间,请写出过程.
答
定义域 2sin(2x+π/3)-1>0 sin(2x+π/3)>1/2
2kπ+π/6