若m2+n2-n+4m+17/4=0,m=_,n=_.

问题描述:

若m2+n2-n+4m+

17
4
=0,m=______,n=______.

∵m2+n2-n+4m+

17
4
=(m2+4m+4)+(n2-n+
1
4
)=(m+2)2+(n-
1
2
2=0,
∴m+2=0,n-
1
2
=0,
∴m=-2,n=
1
2

故答案为:-2,
1
2