已知4x平方+y平方-4x+2y+2=0,求x的y次方

问题描述:

已知4x平方+y平方-4x+2y+2=0,求x的y次方

4x²+y²-4x+2y+2=0
4x²+y²-4x+2y+1+1=0
(4x²-4x+1)+(y²+2y+1)=0
(2x-1)²+(y+1)²=0
2x-1=0
x=0.5
y+1=0
y=-1
x^y
=0.5^-1
=2