100ml0.1mol/l H2SO4 150ML 0.2MOL/L NAOH反应后溶液PH为多少
问题描述:
100ml0.1mol/l H2SO4 150ML 0.2MOL/L NAOH反应后溶液PH为多少
答案是PH=8怎么算出来的呢?
答
n(H2SO4)=0.1×0.1=0.01mol n(NaOH)=0.2×0.15=0.03mol
H2SO4+2NaOH===Na2SO4+2H2O
1 2
0.01 X
X=0.01×2=0.02mol