当y-x=3时,求代数式1/3×(x-y)³+2(x-y)²-2x+2y-6的值

问题描述:

当y-x=3时,求代数式1/3×(x-y)³+2(x-y)²-2x+2y-6的值

y-x=3
所以
1/3×(x-y)³+2(x-y)²-2x+2y-6
=1/3×(x-y)³+2(x-y)²-2(x-y)-6
=-1/3×3³+2×3²-2×(-3)-6
=-9+18+6-6
=9