解方程 (1)2x−12−x+2=5x+2/3−x+3/6 (2)0.4x+0.90.5−0.03+0.02x0.03=x−52.

问题描述:

解方程
(1)

2x−1
2
−x+2=
5x+2
3
x+3
6

(2)
0.4x+0.9
0.5
0.03+0.02x
0.03
x−5
2

(1)去分母得,3(2x-1)-6x+12=2(5x+2)-(x+3),去括号得,6x-3-6x+12=10x+4-x-3,移项得,6x-6x-10x+x=4-3+3-12,合并同类项得,-9x=-8,把系数化为1得,x=89;(2)原方程可化为:4x+95-2x+33=x−52,去分母...