解方程 (1)2x−12−x+2=5x+2/3−x+3/6 (2)0.4x+0.90.5−0.03+0.02x0.03=x−52.
问题描述:
解方程
(1)
−x+2=2x−1 2
−5x+2 3
x+3 6
(2)
−0.4x+0.9 0.5
=0.03+0.02x 0.03
. x−5 2
答
(1)去分母得,3(2x-1)-6x+12=2(5x+2)-(x+3),去括号得,6x-3-6x+12=10x+4-x-3,移项得,6x-6x-10x+x=4-3+3-12,合并同类项得,-9x=-8,把系数化为1得,x=89;(2)原方程可化为:4x+95-2x+33=x−52,去分母...