计算![(b-3a)^2]^﹙n+1﹚*[﹙3a-b﹚^2n+1]^3
问题描述:
计算![(b-3a)^2]^﹙n+1﹚*[﹙3a-b﹚^2n+1]^3
答
[(b-3a)^2]^﹙n+1﹚*[﹙3a-b﹚^2n+1]^3
=[(3a-b)^2]^﹙n+1﹚*[﹙3a-b﹚^2n+1]^3
=(3a-b)^2﹙n+1﹚*﹙3a-b﹚^3(2n+1)
=(3a-b)^(7n+5﹚