若分式方程2/x-(x-m)/(x^-x)=1+1/(x-1)无实数根,求m的值
问题描述：
若分式方程2/x-(x-m)/(x^-x)=1+1/(x-1)无实数根,求m的值
答
2/x-(x-m)/(x^-x)=1+1/(x-1)
2(x-1)-(x-m)=(x^2-x)+x
2x-2-x+m=x^2
x^2-x+2-m=0
因为此方程无实数解,所以:
△=(-1)^2-4(2-m)=1-8+4m=4m-7m