lim n趋于无穷2的n次方sin(x/2的n次方)的极限怎么求
问题描述:
lim n趋于无穷2的n次方sin(x/2的n次方)的极限怎么求
答
sin(x/2的n次方)换成等价的无穷小“x/2的n次方”,那么原式=lim 2的n次方×(x/2的n次方)=x
lim n趋于无穷2的n次方sin(x/2的n次方)的极限怎么求
sin(x/2的n次方)换成等价的无穷小“x/2的n次方”,那么原式=lim 2的n次方×(x/2的n次方)=x