1.已知x²+y²+7 xy+-2求5x²-3xy-4y²-11xy-7x²+2y²的值
问题描述:
1.已知x²+y²+7 xy+-2求5x²-3xy-4y²-11xy-7x²+2y²的值
1.已知x²+y²+7 xy+-2求5x²-3xy-4y²-11xy-7x²+2y²的值
答
5x²-3xy-4y²-11xy-7x²+2y²
=-2x²-2y²-14xy
=-2(x²+y²)-14xy
=-2×7-14×(-2)
=-14+28
=14