如果x/2=y/3=z/5,且xyz不等于0,则(x+y+z)/(3x-y),

问题描述:

如果x/2=y/3=z/5,且xyz不等于0,则(x+y+z)/(3x-y),

x/2=y/3=z/5
所以y=3x/2
z=5x/2
(x+y+z)/(3x-y)
=(x+3x/2+5x/2)/(3x-3x/2)
=5x/(3x/2)
=5/(3/2)
=10/3