当x>3时,化简（3-x）根号2x/9-6x+x²
问题描述：
当x>3时,化简（3-x）根号2x/9-6x+x²
答
（3-x）√2x/9-6x+x²
=(3-x)√2x/(3-x)²
=(3-x)/(x-3)√2x
=-√2x