当x>3时,化简(3-x)根号2x/9-6x+x²
问题描述:
当x>3时,化简(3-x)根号2x/9-6x+x²
答
(3-x)√2x/9-6x+x²
=(3-x)√2x/(3-x)²
=(3-x)/(x-3)√2x
=-√2x