已知5x2-3x-5=0,则5x2-2x-1/5x2−2x−5=_.

问题描述:

已知5x2-3x-5=0,则5x2-2x-

1
5x2−2x−5
=______.

5x2-2x-

1
5x2−2x−5
=x+5-
1
x

∵5x2-3x=5,两边同除以5x得:x-
1
x
=
3
5

∴原式=x+5-
1
x
=
28
5