若实数x y满足,4x^2-y^2-4x+6y+10=0,求x^2+y^2的值

问题描述:

若实数x y满足,4x^2-y^2-4x+6y+10=0,求x^2+y^2的值

是+y^2吧 (4x^2-4x+1)+(y^2+6y+9)=0 (2x-1)^2+(y+3)^2=0
(2x-1)^2>=0,(y+3)^2>=0, (2x-1)^2=0,(y+3)^2=0 x=1/2,y=-3,x^2+y^2=37/4