解方程. (1)x2-2x-2=0; (2)x(2x-3)=(3x+2)(2x-3).
问题描述:
解方程.
(1)x2-2x-2=0;
(2)x(2x-3)=(3x+2)(2x-3).
答
(1)x2-2x-2=0,
b2-4ac=(-2)2-4×1×(-2)=12,
x=
2±
12
2×1
x1=1+
,x2=1-
3
.
3
(2)移项得:x(2x-3)-(3x+2)(2x-3)=0,
(2x-3)(x-3x-2)=0,
2x-3=0,x-3x-2=0,
x1=
,x2=-1.3 2