求解log（1/2）cos(x+π/6)≤1/2,x的取值范围
问题描述：
求解log（1/2）cos(x+π/6)≤1/2,x的取值范围
答
周末练……= =、
答
log（1/2）cos(x+π/6)≤1/2=log(1/2)[(1/2)^1/2]=log(1/2)(√2/2)
log(1/2)x递减
所以cos(x+π/6)≥√2/2=cos(2kπ±π/4)
所以2kπ-π/4≤x+π/6≤2kπ+π/4
2kπ-5π/12≤x≤2kπ+π/12