计算|1/2001|-1/2000+|1/2000-1/1999|-|1/1999-1/2001|
问题描述:
计算|1/2001|-1/2000+|1/2000-1/1999|-|1/1999-1/2001|
答
1/2001-1/20001/2000-1/19991/1999-1/2001>0
所以原式=-(1/2001-1/2000)+[-(1/2000-1/1999)]-(1/1999-1/2001)
=-1/2001+1/2000-1/2000+1/1999-1/1999+1/2001
=0