(1/6)*[(2x-3)^2]-6=0

问题描述:

(1/6)*[(2x-3)^2]-6=0

(1/6)×[(2x-3)²]-6=0
(1/6)×(4x²-12x+9)=6
4x²-12x+9=36
4x²-12x-27=0
(2x-9)(2x+3)=0
x=9/2或x=-3/2