2x+3y-4=0,求4的x次方·8的y次方的值
问题描述：
2x+3y-4=0,求4的x次方·8的y次方的值
答
2x+3y=4
4^x*8^y
=2^(2x)*2^(3y)
=2^(2x+3y)
=2^4
=16