-x4+8x²-16 要当天,

问题描述:

-x4+8x²-16 要当天,

原式=-[(x²)²-8x²+4²]
=-(x²-4)²
=-(x-2)(x+2)²

原式=-(x^4-8x²+16)
=-(x²-4)²
=-(x+2)²(x-2)²

解:
=-(x4-8x2十16)
=-(x2-4)^2
=-(x十2)^2(x-2)^2
希望对你有帮助!

-x^4+8x²-16
=-(x^4-8x+16)
=-(x²-4)²
=-(x+2)²(x-2)²

不明白可追问,祝学习进步!

-x4+8x²-16
=-(x²-4)²
=-(x+2)²(x-2)²