x²－64y²分之2x 减 x－8y分之1
问题描述：
x²－64y²分之2x 减 x－8y分之1
答
通分：[2x-(x+8y)]/(x+8y)(x-8y)=(x-8y)/(x+8y)(x-8y)=1/(x+8y)
望采纳，谢谢
答
原式＝2x/(x²-64y²)-(x+8y)/(x²-64y²)=(2x-x-8y)/(x²-64y²)=1/(x+8y)；
答
x²－64y²是用平方差
答
x²－64y²分之2x 减 x－8y分之1= 2x-(x+8y)/(x²-64y²)=(x-8y)/(x+8y)(x-8y)=1/(x+8y)
答
2x/(x²－64y²) - 1/(x-8y) 根据公式：a²-b²=(a+b)(a-b)
=2x/(x+8y)(x-8y) - 1/(x-8y) 通分
=2x/(x+8y)(x-8y) - (x-8y)/(x+8y)(x-8y)
=(2x-x+8y)/(x+8y)(x-8y)
=(x+8y)/(x+8y)(x-8y)
=1/(x-8y)