当x=3.675,y=2.325时代数式x²+2xy+y²的值是多少?
问题描述：
当x=3.675,y=2.325时代数式x²+2xy+y²的值是多少?
答
x²+2xy+y²=(x+y)²=(3.675+2.325)²=6²=36
答
原式=(x+y)²
=(3.672+2.325)²
=6²
=36
答
x²+2xy+y²
=（x+y）²
=（3.675+2.375）²
=6²
=36