求解一元一次方程:(1)7x-[x-1/2(x-1)]=2/3(x-1)(2)3/4[4/3(1/2x-1/4)-16]=3x+1
问题描述:
求解一元一次方程:(1)7x-[x-1/2(x-1)]=2/3(x-1)(2)3/4[4/3(1/2x-1/4)-16]=3x+1
答
求解一元一次方程:(1)7x-[x-1/2(x-1)]=2/3(x-1)(2)3/4[4/3(1/2x-1/4)-16]=3x+1