函数y=2sin(2x+π/4)的单调递增区间怎么求

问题描述:

函数y=2sin(2x+π/4)的单调递增区间怎么求

2kπ-π/22kπ+π/2

-π/2+2kπ≤2x+π/4≤π/2+2kπ
-3π/4≤2x≤π/4
-3π/8≤x≤π/8
单调区间为[-3π/8,π/8]