函数y=2sin(2x+π/4)的单调递增区间怎么求
问题描述:
函数y=2sin(2x+π/4)的单调递增区间怎么求
答
2kπ-π/22kπ+π/2
答
-π/2+2kπ≤2x+π/4≤π/2+2kπ
-3π/4≤2x≤π/4
-3π/8≤x≤π/8
单调区间为[-3π/8,π/8]