因式分解;第三题:9x²-6x+1-y²
问题描述:
因式分解;第三题:9x²-6x+1-y²
答
9x²-6x+1-y²
=(3x-1)^2-y^2
=(3x+y-1)(3x-y-1)
答
原式=(3x-1)^2 -y^2=(3x-1 y)(3x-1-y)
答
原式=(3x-1)²-y²
=(3x-1+y)(3x-1-y)
答
9x²-6x+1-y²
=(9x²-6x+1)-y²
=(3x-1)²-y²
=(3x+y-1)(3x-y-1)
答
9x²-6x+1-y²
=(9x²-6x+1)-y²
=(3X-1)方-Y方
用平方差公式来做
=(3x+y-1)(3x-y-1)
不懂的欢迎追问,
答
9x²-6x+1-y²
=(3x-1)^2-y^2
=(3x-1+y)(3x-1-y)