求对数方程根log3为底(x^2-10)=1+log3为底x
问题描述：
求对数方程根log3为底(x^2-10)=1+log3为底x
答
log3(x²-10)=1+log3(x)
log3(x²-10)=log3(3)+log3(x)
log3(x²-10)=log3(3x)
x²-10=3x
x1=-2,x2=5