log (log2)^2 - (log4)(log20) + (log20)^2
问题描述:
log
(log2)^2 - (log4)(log20) + (log20)^2
答
原式=(log2)^2 - 2(log2)(log20) + (log20)^2=(log2-log20)^2=(log10)^2=1
答
(log2)^2 - (log4)(log20) + (log20)^2
=(log2)^2 - 2 (log2)(log20) + (log20)^2
=[lg2-lg20]^2
=[-lg10]^2
=[-1]^2
=1