1-根号3i/(根号3+i)的平方等于平方是根号3+i的平方，不是整体的平方

也差不多，用两种方法：
(1－根号3i)/(根号3＋i)^2
＝(1－根号3i)/[i(1－根号3i)(根号3＋i)]
＝1/[i(根号3＋i)]
＝1/(－1＋根号3·i)
＝(－1－根号3·i)/[(－1＋根号3·i)·(－1－根号3·i)]
＝(－1－根号3·i)/4
或用三角函数：
(1－根号3i)/(根号3＋i)^2
＝2(1/2－根号3/2·i)/[2(根号3/2＋1/2·i)]^2
＝2[cos(－π/3)＋isin(－π/3)]/[4·(cosπ/6＋isinπ/6)^2]
＝1/2·[cos(－π/3)＋isin(－π/3)]/(cosπ/3＋isinπ/3)
＝1/2·[cos(－π/3－π/3)＋isin(－π/3－π/3)]
＝1/2·[cos(－2π/3)＋isin(－2π/3)]
＝1/2·[－1/2＋i·(－根号3/2)]
＝－1/4－根号3/4·i

原式=(1-√3i)/(√3+i)^2
=(1-√3i)/(2+2√3i)
=(1-√3i)^2/[2*(1-3)]
=(-2-2√3i)/(-4)
=(1+√3i)/2.
若前面没有括号,
原式=1-√3i/(√3+i)^2
=（7+√3i）/4.