x四次方-3x2+1 x四次方+2x2+9 怎么因式分解?
问题描述：
x四次方-3x2+1 x四次方+2x2+9 怎么因式分解?
答
x四次方-3x2+1 =x四次方-2X²+1-X²
=（X²-1)²-X²
=(X²+X-1)(X²-X-1)
x四次方+2x2+9 =
=x四次方+6X²+9-4X²
=(X²+3)²-(2x)²
=(X²+2X+3)(X²-2X+3)
答
x^4-3x2+1 =x^4-2X²+1-X²=（X²-1)²-X²=(X²+X-1)(X²-X-1)x^4+2x2+9 ==x^4+6X²+9-4X²=(X²+3)²-(2x)²=(X²+2X+3)(X²-2X+3)