化简（x³+3）/（x²-1）-（x+1）/（x-1）+1等于多少?
问题描述：
化简（x³+3）/（x²-1）-（x+1）/（x-1）+1等于多少?
答
原式=（x³+3）/（x²-1）-（x+1)²/（x²-1）+（x²-1）/（x²-1）
=[x³+3-（x²+2x+1）+（x²-1）] /（x²-1）
=(x³-2x+1)/（x²-1）
=[x（x²-1）-（x-1)] /（x²-1）
=x - 1/(x+1)
答
错了,第一个是x²+3原式=(x²+3)/(x+1)(x-1)-(x+1)²/(x+1)(x-1)+(x+1)(x-1)/(x+1)(x-1)=(x²+3-x²-2x-1+x²-1)/(x+1)(x-1)=(x²-2x+1)/(x+1)(x-1)=(x--1)²/(x+1)(x-1)=(x-1)/(x+...