配制0.2mol/lH2SO4溶液500ml,需98%的浓H2SO4(密度1.84g/cm³)____ml
问题描述:
配制0.2mol/lH2SO4溶液500ml,需98%的浓H2SO4(密度1.84g/cm³)____ml
答
0.2*0.5=1.84*0.98*x/98,0.5是500ml换算到L,x即为所求
配制0.2mol/lH2SO4溶液500ml,需98%的浓H2SO4(密度1.84g/cm³)____ml
0.2*0.5=1.84*0.98*x/98,0.5是500ml换算到L,x即为所求