已知A(2,3)B(-2,1),动点P满足向量OP=t向量OA+(1-t)向量OB,则点P的轨迹方程是
问题描述:
已知A(2,3)B(-2,1),动点P满足向量OP=t向量OA+(1-t)向量OB,则点P的轨迹方程是
答
let OP be (x,y)OP=tOA+(1-t)OB(x,y)=t(2,3)+(1-t)(-2,1) =(4t-2, 2t+1)x = 4t-2 (1)y = 2t+1 (2)(1) - 2(2)x-2y = -4