log3(log4x)=log4(log2y)=log2(log3z)=1
问题描述:
log3(log4x)=log4(log2y)=log2(log3z)=1
答
log3(log4x)=1
log4x=3
x=64
log4(log2y)=1
log2y=4
y=16
log2(log3z)=1
log3z=2
z=9
答
log3(log4x)=log4(log2y)=log2(log3z)=1
即:
log4x=3
log2y=4
log3z=2
得:
x=4^3=64
y=2^4=16
z=3^2=9
答
log3(log4x)=log4(log2y)=log2(log3z)=1
log4(x)=3 x=64
log2(y)=4 y=16
log3(z)=2 z=9
x=64 y=16 z=9