dy/dx=y+cosx 是多少
问题描述:
dy/dx=y+cosx 是多少
答
∵dy/dx=y+cosx ==>dy-ydx=cosxdx ==>dy/e^x-ydx/e^x=cosxdx/e^x (等式两端同除e^x) ==>d(y/e^x)=d((sinx-cosx)/(2e^x)) ==>y/e^x=d((sinx-cosx)/(2e^x)+C (...