3(y-1)-(y+1)/3=1

问题描述:

3(y-1)-(y+1)/3=1

去分母两边同时乘以3
6(y-1)-(y+1)=3
6y-6-y-1=3
5y=3+1+6
y=2

Y=13/8

3(y-1)-(y+1)/3=1
方程两边同时乘以3得,
9(y-1)-(y+1)=3
去括号得,
9y-9-y-1=3
移项合并得,
8y=13
方程两边同时除以8得,
y=13/8

3(y-1)-(y+1)/3=1
3y-3-y/3-1/3=1
8y/3=13/3
y=13/8